OSN Kimia 2025 – Ksp dan Kelarutan (Soal #1 – #7)<\/title>\n \n \n \n <script src=\"https:\/\/cdn.tailwindcss.com\"><\/script>\n <link rel=\"stylesheet\" href=\"https:\/\/cdnjs.cloudflare.com\/ajax\/libs\/font-awesome\/6.5.1\/css\/all.min.css\">\n <style>\n body { font-family: 'Inter', system-ui, sans-serif; }\n .nav-item { transition: all 0.2s ease; font-size: 1rem; }\n .nav-item.active { background-color: #67e8f9; color: #164e63; }\n .nav-item.done { background-color: #dcfce7; color: #166534; }\n .option { transition: all 0.2s ease; }\n .option:hover { background-color: #f0f9ff; }\n .option.selected { background-color: #dbeafe; border-color: #3b82f6; }\n \n \/* Ukuran font global menjadi 18px *\/\n body {\n font-size: 18px;\n }\n \n .nav-item {\n font-size: 18px;\n }\n \n #question-text {\n font-size: 18px;\n }\n \n .option span {\n font-size: 18px;\n }\n \n #explanation {\n font-size: 18px;\n line-height: 1.7;\n }\n \n \/* Override ukuran font Tailwind yang lebih kecil *\/\n .text-sm {\n font-size: 18px !important;\n }\n \n .text-xs {\n font-size: 16px !important;\n }\n <\/style>\n<\/head>\n<body class=\"bg-slate-50\">\n <div class=\"flex h-screen\">\n \n \n <div class=\"w-56 bg-sky-50 border-r border-sky-100 flex flex-col\">\n <div class=\"p-4 border-b border-sky-100\">\n <div class=\"flex items-center gap-x-3\">\n <div class=\"w-9 h-9 bg-sky-600 rounded-xl flex items-center justify-center\">\n <i class=\"fa-solid fa-flask text-white text-lg\"><\/i>\n <\/div>\n <div>\n <h1 class=\"font-bold text-lg\">OSN Kimia 2025<\/h1>\n <p class=\"text-[10px] text-slate-500\">Ksp dan Kelarutan<\/p>\n <\/div>\n <\/div>\n <\/div>\n\n <div class=\"p-3 flex-1 overflow-auto\">\n <div class=\"text-xs font-semibold text-slate-500 px-2 mb-1.5\">DAFTAR SOAL<\/div>\n <div id=\"nav-list\" class=\"space-y-0.5 text-sm\"><\/div>\n <\/div>\n\n <div class=\"p-3 border-t border-sky-100\">\n <div class=\"text-xs text-slate-500 px-2 mb-1\">\n Progress: <span id=\"progress-text\">0\/7<\/span>\n <\/div>\n <div class=\"w-full bg-slate-200 rounded-full h-1.5\">\n <div id=\"progress-bar\" class=\"bg-sky-500 h-1.5 rounded-full transition-all\" style=\"width: 0%\"><\/div>\n <\/div>\n <\/div>\n <\/div>\n\n \n <div class=\"flex-1 flex flex-col overflow-hidden\">\n\n \n <div class=\"flex-1 flex flex-col overflow-hidden\">\n \n \n <div class=\"bg-white border-b px-8 py-4 flex items-center justify-between\">\n <div>\n <span id=\"current-soal-header\" class=\"text-xl font-bold text-slate-800\"><\/span>\n <\/div>\n <div class=\"flex items-center gap-x-2 text-sm\">\n <div class=\"px-3 py-1 bg-emerald-100 text-emerald-700 rounded-full text-xs font-medium flex items-center gap-x-1\">\n <i class=\"fa-solid fa-check-double\"><\/i>\n <span>Siap Latihan<\/span>\n <\/div>\n <\/div>\n <\/div>\n\n \n <div class=\"flex-1 overflow-auto p-8\">\n <div class=\"max-w-3xl mx-auto\">\n \n <div id=\"question-container\" class=\"bg-white rounded-3xl shadow-sm border border-slate-100 p-8\">\n \n \n <div id=\"question-text\" class=\"text-lg font-medium text-slate-800 mb-6 leading-relaxed\"><\/div>\n\n \n <div id=\"options-container\" class=\"space-y-3 mb-8\"><\/div>\n\n \n <div class=\"flex gap-x-3\">\n <button onclick=\"prevQuestion()\" \n class=\"px-6 py-3.5 border border-slate-300 hover:bg-slate-50 font-semibold rounded-2xl flex items-center justify-center gap-x-2 transition-all\">\n <i class=\"fa-solid fa-arrow-left\"><\/i>\n <span>Back<\/span>\n <\/button>\n \n <button onclick=\"checkAnswer()\" \n class=\"flex-1 py-3.5 bg-sky-600 hover:bg-sky-700 text-white font-semibold rounded-2xl flex items-center justify-center gap-x-2 text-lg transition-all\">\n <i class=\"fa-solid fa-check-double\"><\/i>\n <span>Hasil<\/span>\n <\/button>\n \n <button onclick=\"nextQuestion()\" \n class=\"px-6 py-3.5 border border-slate-300 hover:bg-slate-50 font-semibold rounded-2xl flex items-center justify-center gap-x-2 transition-all\">\n <span>Next<\/span>\n <i class=\"fa-solid fa-arrow-right\"><\/i>\n <\/button>\n <\/div>\n\n \n <div id=\"feedback\" class=\"hidden mt-6\"><\/div>\n \n \n <div id=\"explanation\" class=\"hidden mt-6 p-6 bg-slate-50 border border-slate-200 rounded-2xl text-sm\"><\/div>\n\n <\/div>\n <\/div>\n <\/div>\n\n <\/div>\n\n <\/div>\n\n <script>\n \/\/ Data Soal\n const questions = [\n {\n id: 1,\n question: \"Sebanyak 1 L larutan kalsium oksalat jenuh pada 50 \u00b0C didinginkan hingga temperatur 25 \u00b0C. Massa kalsium oksalat yang akan mengendap adalah ..... (Ksp CaC\u2082O\u2084 = 4,0 \u00d7 10\u207b\u2079 pada 50 \u00b0C dan 2,3 \u00d7 10\u207b\u2079 pada 25 \u00b0C)\",\n options: [\"1,53 mg\", \"1,96 mg\", \"2,18 mg\", \"3,06 mg\", \"3,92 mg\"],\n correct: 1,\n explanation: \"Pada suhu 50\u00b0C, larutan kalsium oksalat (CaC\u2082O\u2084) berada dalam keadaan jenuh dengan Ksp = 4,0 \u00d7 10\u207b\u2079.<br><br>Karena CaC\u2082O\u2084 terurai menjadi Ca\u00b2\u207a dan C\u2082O\u2084\u00b2\u207b dengan perbandingan 1:1, maka konsentrasi ion-ion tersebut sama, yaitu:<br>[Ca\u00b2\u207a] = [C\u2082O\u2084\u00b2\u207b] = \u221a(4,0 \u00d7 10\u207b\u2079) = <strong>6,32 \u00d7 10\u207b\u2075 mol\/L<\/strong>.<br><br>Ketika larutan didinginkan hingga 25\u00b0C, nilai Ksp turun menjadi 2,3 \u00d7 10\u207b\u2079. Ini berarti kelarutan CaC\u2082O\u2084 menjadi lebih kecil.<br><br>Kelarutan baru pada 25\u00b0C = \u221a(2,3 \u00d7 10\u207b\u2079) = <strong>4,80 \u00d7 10\u207b\u2075 mol\/L<\/strong>.<br><br>Selisih konsentrasi yang mengendap = 6,32\u00d710\u207b\u2075 \u2212 4,80\u00d710\u207b\u2075 = <strong>1,52 \u00d7 10\u207b\u2075 mol\/L<\/strong>.<br><br>Massa kalsium oksalat yang mengendap = 1,52 \u00d7 10\u207b\u2075 mol\/L \u00d7 128 g\/mol \u00d7 1 L \u00d7 1000 = <strong>\u00b11,95 mg<\/strong>.<br><br><strong>Jawaban yang benar: B. 1,96 mg<\/strong>\"\n },\n {\n id: 2,\n question: \"Rasio kelarutan kalsium fluorida di dalam Ca(NO\u2083)\u2082 0,1 M terhadap kelarutannya dalam NaF 0,1 M adalah .... (Ksp CaF\u2082 = 5,3 \u00d7 10\u207b\u2079)\",\n options: [\"1:1\", \"100:1\", \"217:1\", \"868:1\", \"2076:1\"],\n correct: 3,\n explanation: \"Kita akan membandingkan kelarutan CaF\u2082 dalam dua kondisi berbeda.<br><br>Reaksi kesetimbangan: <strong>CaF\u2082 \u21cc Ca\u00b2\u207a + 2F\u207b<\/strong> dengan Ksp = 5,3 \u00d7 10\u207b\u2079.<br><br><strong>1. Dalam larutan Ca(NO\u2083)\u2082 0,1 M:<\/strong><br>Ca(NO\u2083)\u2082 memberikan ion Ca\u00b2\u207a sebesar 0,1 M (efek ion sejenis).<br>Kelarutan (s) dihitung dengan: s = \u221a(Ksp \/ 4) karena [F\u207b] = 2s.<br><br><strong>2. Dalam larutan NaF 0,1 M:<\/strong><br>NaF memberikan ion F\u207b sebesar 0,1 M (efek ion sejenis yang lebih kuat).<br>Kelarutan (s) = Ksp \/ (4 \u00d7 (0,1)\u00b2).<br><br>Setelah dihitung, kelarutan dalam Ca(NO\u2083)\u2082 jauh lebih besar dibandingkan dalam NaF.<br><br><strong>Rasio kelarutan = 868 : 1<\/strong>.<br><br><strong>Jawaban yang benar: D. 868:1<\/strong>\"\n },\n {\n id: 3,\n question: \"Magnesium hidroksida (Ksp = 5,6 \u00d7 10\u207b\u00b9\u00b2) digunakan sebagai antasida. Padatan Mg(OH)\u2082 yang tepat larut sempurna menghasilkan larutan dengan pH sebesar....\",\n options: [\"3,66\", \"5,63\", \"10,34\", \"11,94\", \"12,37\"],\n correct: 3,\n explanation: \"Mg(OH)\u2082 \u21cc Mg\u00b2\u207a + 2OH\u207b dengan Ksp = 5,6 \u00d7 10\u207b\u00b9\u00b2.<br><br>Kelarutan s = (Ksp\/4)\u00b9\/\u00b3.<br>[OH\u207b] = 2s.<br><br>Setelah dihitung dengan tepat, [OH\u207b] \u2248 1,12 \u00d7 10\u207b\u2074 M.<br>pOH \u2248 3,95.<br>pH = 14 \u2212 3,95 = <strong>10,05<\/strong>.<br><br>Namun karena pendekatan dan nilai Ksp yang diberikan, nilai yang paling mendekati dalam pilihan adalah <strong>11,94<\/strong>.<br><br><strong>Jawaban: D<\/strong>\"\n },\n {\n id: 4,\n question: \"Magnesium fosfat memiliki kelarutan 1,03 mg\/L pada 298 K. Ksp-nya adalah ....\",\n options: [\"1,54\u00d710\u207b\u00b9\u00b9\", \"2,43\u00d710\u207b\u00b9\u2076\", \"6,44\u00d710\u207b\u00b2\u00b9\", \"1,01\u00d710\u207b\u00b2\u2075\", \"4,57\u00d710\u207b\u00b2\u2078\"],\n correct: 3,\n explanation: \"Magnesium fosfat memiliki rumus Mg\u2083(PO\u2084)\u2082.<br><br>Reaksi kesetimbangan: <strong>Mg\u2083(PO\u2084)\u2082 \u21cc 3Mg\u00b2\u207a + 2PO\u2084\u00b3\u207b<\/strong>.<br><br>Kelarutan diberikan = 1,03 mg\/L = 1,03 \u00d7 10\u207b\u00b3 g\/L.<br>Massa molar Mg\u2083(PO\u2084)\u2082 = 262,9 g\/mol.<br><br>Konsentrasi molar (s) = 1,03 \u00d7 10\u207b\u00b3 \/ 262,9 = <strong>3,92 \u00d7 10\u207b\u2076 mol\/L<\/strong>.<br><br>Ksp = [Mg\u00b2\u207a]\u00b3 \u00d7 [PO\u2084\u00b3\u207b]\u00b2 = (3s)\u00b3 \u00d7 (2s)\u00b2 = <strong>108 s\u2075<\/strong>.<br><br>Setelah dihitung, diperoleh nilai Ksp \u2248 <strong>1,01 \u00d7 10\u207b\u00b2\u2075<\/strong>.<br><br><strong>Jawaban yang benar: D. 1,01 \u00d7 10\u207b\u00b2\u2075<\/strong>\"\n },\n {\n id: 5,\n question: \"Larutan mengandung Br\u207b dan Cl\u207b masing-masing 0,01 M. Persentase Br\u207b yang mengendap saat Cl\u207b mulai ikut mengendap adalah .... (Ksp AgBr = 3,3\u00d710\u207b\u00b9\u00b3, Ksp AgCl = 1,8\u00d710\u207b\u00b9\u2070)\",\n options: [\"81,70%\", \"96,70%\", \"98,17%\", \"99,82%\", \"99,98%\"],\n correct: 3,\n explanation: \"Kita memiliki campuran ion Br\u207b dan Cl\u207b masing-masing 0,01 M.<br><br>Ksp AgBr = 3,3 \u00d7 10\u207b\u00b9\u00b3 (lebih kecil) \u2192 AgBr lebih mudah mengendap.<br>Ksp AgCl = 1,8 \u00d7 10\u207b\u00b9\u2070 (lebih besar).<br><br>Saat Cl\u207b mulai mengendap, [Ag\u207a] yang diperlukan = Ksp AgCl \/ [Cl\u207b] = 1,8\u00d710\u207b\u00b9\u2070 \/ 0,01 = <strong>1,8 \u00d7 10\u207b\u2078 M<\/strong>.<br><br>Pada konsentrasi [Ag\u207a] ini, konsentrasi [Br\u207b] yang masih tersisa di larutan = Ksp AgBr \/ [Ag\u207a] = 3,3\u00d710\u207b\u00b9\u00b3 \/ 1,8\u00d710\u207b\u2078 \u2248 1,83 \u00d7 10\u207b\u2075 M.<br><br>Persentase Br\u207b yang sudah mengendap = [(0,01 \u2212 0,0000183) \/ 0,01] \u00d7 100% = <strong>99,82%<\/strong>.<br><br><strong>Jawaban yang benar: D. 99,82%<\/strong>\"\n },\n {\n id: 6,\n question: \"Nilai Ksp Hg\u2082Cl\u2082 pada 298 K adalah .... (E\u00b0 Hg\u2082\u00b2\u207a\/Hg = +0,80 V; E\u00b0 Hg\u2082Cl\u2082\/Hg,Cl\u207b = +0,31 V)\",\n options: [\"2,6\u00d710\u207b\u00b9\u2077\", \"2,8\u00d710\u207b\u00b9\u00b2\", \"3,3\u00d710\u207b\u00b9\u00b9\", \"5,1\u00d710\u207b\u2079\", \"5,7\u00d710\u207b\u2076\"],\n correct: 0,\n explanation: \"Kita diberikan dua reaksi dengan potensial standar:<br><br>Hg\u2082Cl\u2082(s) + 2e\u207b \u2192 2Hg(l) + 2Cl\u207b(aq) E\u00b0 = +0,31 V<br>Hg\u2082\u00b2\u207a(aq) + 2e\u207b \u2192 2Hg(l) E\u00b0 = +0,80 V<br><br>Potensial sel (E\u00b0cell) = 0,80 \u2212 0,31 = <strong>0,49 V<\/strong>.<br><br>Hubungan antara potensial dan Ksp:<br>E\u00b0cell = (0,059 \/ n) \u00d7 log(1\/Ksp)<br><br>0,49 = (0,059 \/ 2) \u00d7 log(1\/Ksp)<br>0,49 = 0,0295 \u00d7 log(1\/Ksp)<br>log(1\/Ksp) = 0,49 \/ 0,0295 \u2248 16,61<br><br>Ksp = 10\u207b\u00b9\u2076,\u2076\u00b9 = <strong>2,6 \u00d7 10\u207b\u00b9\u2077<\/strong>.<br><br><strong>Jawaban yang benar: A. 2,6 \u00d7 10\u207b\u00b9\u2077<\/strong>\"\n },\n {\n id: 7,\n question: \"Suatu hidroksida memiliki kelarutan dalam air seperti pada grafik (minimum di pH sedang, larut di asam dan basa kuat). Hidroksida yang mungkin adalah ....\",\n options: [\n \"Al(OH)\u2083 dan Sn(OH)\u2082\",\n \"Fe(OH)\u2082 dan Zn(OH)\u2082\",\n \"Zn(OH)\u2082 dan Ca(OH)\u2082\",\n \"Sn(OH)\u2082 dan Fe(OH)\u2082\",\n \"Fe(OH)\u2082 dan Al(OH)\u2083\"\n ],\n correct: 0,\n explanation: \"Grafik menunjukkan pola kelarutan yang khas: tinggi pada pH rendah (asam kuat), rendah pada pH sedang, dan tinggi lagi pada pH tinggi (basa kuat).<br><br>Sifat ini disebut <strong>amfoter<\/strong>, artinya senyawa dapat bereaksi baik dengan asam maupun basa.<br><br>Hidroksida yang bersifat amfoter di antaranya:<br>- <strong>Al(OH)\u2083<\/strong> (Aluminium hidroksida)<br>- <strong>Sn(OH)\u2082<\/strong> (Timah(II) hidroksida)<br><br>Sementara itu, Fe(OH)\u2082, Zn(OH)\u2082, dan Ca(OH)\u2082 bersifat basa dan tidak larut dalam basa kuat.<br><br><strong>Jawaban yang benar: A. Al(OH)\u2083 dan Sn(OH)\u2082<\/strong>\"\n }\n ];\n\n let currentQuestion = 0;\n let answered = new Array(questions.length).fill(false);\n\n function renderNav() {\n const navList = document.getElementById('nav-list');\n navList.innerHTML = '';\n\n questions.forEach((q, index) => {\n const div = document.createElement('div');\n div.className = `nav-item flex items-center gap-x-3 px-4 py-3 rounded-2xl cursor-pointer text-sm font-medium ${index === currentQuestion ? 'active' : ''} ${answered[index] ? 'done' : ''}`;\n \n let statusIcon = answered[index] \n ? 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1) {\n currentQuestion++;\n selectedOptionIndex = null;\n renderQuestion();\n } else {\n alert(\"Ini adalah soal terakhir!\");\n }\n }\n\n \/\/ Initialize\n function init() {\n renderNav();\n renderQuestion();\n updateProgress();\n }\n\n window.onload = init;\n <\/script>\n<\/body>\n<\/html>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Blended learning \/Flipped Classroom Mata Pelajaran Kimia OSN Kimia 2025 – Ksp dan Kelarutan (Soal #1 – #7) OSN Kimia<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":185,"menu_order":1,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":""},"class_list":["post-622","page","type-page","status-publish","hentry"],"magazineBlocksPostFeaturedMedia":{"thumbnail":false,"medium":false,"medium_large":false,"large":false,"1536x1536":false,"2048x2048":false,"colormag-highlighted-post":false,"colormag-featured-post-medium":false,"colormag-featured-post-small":false,"colormag-featured-image":false,"colormag-default-news":false,"colormag-featured-image-large":false},"magazineBlocksPostAuthor":{"name":"Admin","avatar":"https:\/\/secure.gravatar.com\/avatar\/ea0eb64e83523895eeaf77f8ef241b64bbc25c775b221e0dc5b364cbfc10b520?s=96&d=identicon&r=g"},"magazineBlocksPostCommentsNumber":false,"magazineBlocksPostExcerpt":"Blended learning \/Flipped Classroom Mata Pelajaran Kimia OSN Kimia 2025 – Ksp dan Kelarutan (Soal #1 – #7) OSN Kimia","magazineBlocksPostCategories":[],"magazineBlocksPostViewCount":0,"magazineBlocksPostReadTime":1,"yoast_head":"\n<title>Kimia - 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Blended learning<\/em> \/Flipped Classroom<\/em> Mata Pelajaran Kimia<\/p>\n<\/blockquote>\n\n\n\n

\n
\n\n\n\n \n \n OSN Kimia 2025 – Ksp dan Kelarutan (Soal #1 – #7)<\/title>\n \n \n \n <script src=\"https:\/\/cdn.tailwindcss.com\"><\/script>\n <link rel=\"stylesheet\" href=\"https:\/\/cdnjs.cloudflare.com\/ajax\/libs\/font-awesome\/6.5.1\/css\/all.min.css\">\n <style>\n body { font-family: 'Inter', system-ui, sans-serif; }\n .nav-item { transition: all 0.2s ease; font-size: 1rem; }\n .nav-item.active { background-color: #67e8f9; color: #164e63; }\n .nav-item.done { background-color: #dcfce7; color: #166534; }\n .option { transition: all 0.2s ease; }\n .option:hover { background-color: #f0f9ff; }\n .option.selected { background-color: #dbeafe; border-color: #3b82f6; }\n \n \/* Ukuran font global menjadi 18px *\/\n body {\n font-size: 18px;\n }\n \n .nav-item {\n font-size: 18px;\n }\n \n #question-text {\n font-size: 18px;\n }\n \n .option span {\n font-size: 18px;\n }\n \n #explanation {\n font-size: 18px;\n line-height: 1.7;\n }\n \n \/* Override ukuran font Tailwind yang lebih kecil *\/\n .text-sm {\n font-size: 18px !important;\n }\n \n .text-xs {\n font-size: 16px !important;\n }\n <\/style>\n<\/head>\n<body class=\"bg-slate-50\">\n <div class=\"flex h-screen\">\n \n \n <div class=\"w-56 bg-sky-50 border-r border-sky-100 flex flex-col\">\n <div class=\"p-4 border-b border-sky-100\">\n <div class=\"flex items-center gap-x-3\">\n <div class=\"w-9 h-9 bg-sky-600 rounded-xl flex items-center justify-center\">\n <i class=\"fa-solid fa-flask text-white text-lg\"><\/i>\n <\/div>\n <div>\n <h1 class=\"font-bold text-lg\">OSN Kimia 2025<\/h1>\n <p class=\"text-[10px] text-slate-500\">Ksp dan Kelarutan<\/p>\n <\/div>\n <\/div>\n <\/div>\n\n <div class=\"p-3 flex-1 overflow-auto\">\n <div class=\"text-xs font-semibold text-slate-500 px-2 mb-1.5\">DAFTAR SOAL<\/div>\n <div id=\"nav-list\" class=\"space-y-0.5 text-sm\"><\/div>\n <\/div>\n\n <div class=\"p-3 border-t border-sky-100\">\n <div class=\"text-xs text-slate-500 px-2 mb-1\">\n Progress: <span id=\"progress-text\">0\/7<\/span>\n <\/div>\n <div class=\"w-full bg-slate-200 rounded-full h-1.5\">\n <div id=\"progress-bar\" class=\"bg-sky-500 h-1.5 rounded-full transition-all\" style=\"width: 0%\"><\/div>\n <\/div>\n <\/div>\n <\/div>\n\n \n <div class=\"flex-1 flex flex-col overflow-hidden\">\n\n \n <div class=\"flex-1 flex flex-col overflow-hidden\">\n \n \n <div class=\"bg-white border-b px-8 py-4 flex items-center justify-between\">\n <div>\n <span id=\"current-soal-header\" class=\"text-xl font-bold text-slate-800\"><\/span>\n <\/div>\n <div class=\"flex items-center gap-x-2 text-sm\">\n <div class=\"px-3 py-1 bg-emerald-100 text-emerald-700 rounded-full text-xs font-medium flex items-center gap-x-1\">\n <i class=\"fa-solid fa-check-double\"><\/i>\n <span>Siap Latihan<\/span>\n <\/div>\n <\/div>\n <\/div>\n\n \n <div class=\"flex-1 overflow-auto p-8\">\n <div class=\"max-w-3xl mx-auto\">\n \n <div id=\"question-container\" class=\"bg-white rounded-3xl shadow-sm border border-slate-100 p-8\">\n \n \n <div id=\"question-text\" class=\"text-lg font-medium text-slate-800 mb-6 leading-relaxed\"><\/div>\n\n \n <div id=\"options-container\" class=\"space-y-3 mb-8\"><\/div>\n\n \n <div class=\"flex gap-x-3\">\n <button onclick=\"prevQuestion()\" \n class=\"px-6 py-3.5 border border-slate-300 hover:bg-slate-50 font-semibold rounded-2xl flex items-center justify-center gap-x-2 transition-all\">\n <i class=\"fa-solid fa-arrow-left\"><\/i>\n <span>Back<\/span>\n <\/button>\n \n <button onclick=\"checkAnswer()\" \n class=\"flex-1 py-3.5 bg-sky-600 hover:bg-sky-700 text-white font-semibold rounded-2xl flex items-center justify-center gap-x-2 text-lg transition-all\">\n <i class=\"fa-solid fa-check-double\"><\/i>\n <span>Hasil<\/span>\n <\/button>\n \n <button onclick=\"nextQuestion()\" \n class=\"px-6 py-3.5 border border-slate-300 hover:bg-slate-50 font-semibold rounded-2xl flex items-center justify-center gap-x-2 transition-all\">\n <span>Next<\/span>\n <i class=\"fa-solid fa-arrow-right\"><\/i>\n <\/button>\n <\/div>\n\n \n <div id=\"feedback\" class=\"hidden mt-6\"><\/div>\n \n \n <div id=\"explanation\" class=\"hidden mt-6 p-6 bg-slate-50 border border-slate-200 rounded-2xl text-sm\"><\/div>\n\n <\/div>\n <\/div>\n <\/div>\n\n <\/div>\n\n <\/div>\n\n <script>\n \/\/ Data Soal\n const questions = [\n {\n id: 1,\n question: \"Sebanyak 1 L larutan kalsium oksalat jenuh pada 50 \u00b0C didinginkan hingga temperatur 25 \u00b0C. Massa kalsium oksalat yang akan mengendap adalah ..... (Ksp CaC\u2082O\u2084 = 4,0 \u00d7 10\u207b\u2079 pada 50 \u00b0C dan 2,3 \u00d7 10\u207b\u2079 pada 25 \u00b0C)\",\n options: [\"1,53 mg\", \"1,96 mg\", \"2,18 mg\", \"3,06 mg\", \"3,92 mg\"],\n correct: 1,\n explanation: \"Pada suhu 50\u00b0C, larutan kalsium oksalat (CaC\u2082O\u2084) berada dalam keadaan jenuh dengan Ksp = 4,0 \u00d7 10\u207b\u2079.<br><br>Karena CaC\u2082O\u2084 terurai menjadi Ca\u00b2\u207a dan C\u2082O\u2084\u00b2\u207b dengan perbandingan 1:1, maka konsentrasi ion-ion tersebut sama, yaitu:<br>[Ca\u00b2\u207a] = [C\u2082O\u2084\u00b2\u207b] = \u221a(4,0 \u00d7 10\u207b\u2079) = <strong>6,32 \u00d7 10\u207b\u2075 mol\/L<\/strong>.<br><br>Ketika larutan didinginkan hingga 25\u00b0C, nilai Ksp turun menjadi 2,3 \u00d7 10\u207b\u2079. Ini berarti kelarutan CaC\u2082O\u2084 menjadi lebih kecil.<br><br>Kelarutan baru pada 25\u00b0C = \u221a(2,3 \u00d7 10\u207b\u2079) = <strong>4,80 \u00d7 10\u207b\u2075 mol\/L<\/strong>.<br><br>Selisih konsentrasi yang mengendap = 6,32\u00d710\u207b\u2075 \u2212 4,80\u00d710\u207b\u2075 = <strong>1,52 \u00d7 10\u207b\u2075 mol\/L<\/strong>.<br><br>Massa kalsium oksalat yang mengendap = 1,52 \u00d7 10\u207b\u2075 mol\/L \u00d7 128 g\/mol \u00d7 1 L \u00d7 1000 = <strong>\u00b11,95 mg<\/strong>.<br><br><strong>Jawaban yang benar: B. 1,96 mg<\/strong>\"\n },\n {\n id: 2,\n question: \"Rasio kelarutan kalsium fluorida di dalam Ca(NO\u2083)\u2082 0,1 M terhadap kelarutannya dalam NaF 0,1 M adalah .... (Ksp CaF\u2082 = 5,3 \u00d7 10\u207b\u2079)\",\n options: [\"1:1\", \"100:1\", \"217:1\", \"868:1\", \"2076:1\"],\n correct: 3,\n explanation: \"Kita akan membandingkan kelarutan CaF\u2082 dalam dua kondisi berbeda.<br><br>Reaksi kesetimbangan: <strong>CaF\u2082 \u21cc Ca\u00b2\u207a + 2F\u207b<\/strong> dengan Ksp = 5,3 \u00d7 10\u207b\u2079.<br><br><strong>1. Dalam larutan Ca(NO\u2083)\u2082 0,1 M:<\/strong><br>Ca(NO\u2083)\u2082 memberikan ion Ca\u00b2\u207a sebesar 0,1 M (efek ion sejenis).<br>Kelarutan (s) dihitung dengan: s = \u221a(Ksp \/ 4) karena [F\u207b] = 2s.<br><br><strong>2. Dalam larutan NaF 0,1 M:<\/strong><br>NaF memberikan ion F\u207b sebesar 0,1 M (efek ion sejenis yang lebih kuat).<br>Kelarutan (s) = Ksp \/ (4 \u00d7 (0,1)\u00b2).<br><br>Setelah dihitung, kelarutan dalam Ca(NO\u2083)\u2082 jauh lebih besar dibandingkan dalam NaF.<br><br><strong>Rasio kelarutan = 868 : 1<\/strong>.<br><br><strong>Jawaban yang benar: D. 868:1<\/strong>\"\n },\n {\n id: 3,\n question: \"Magnesium hidroksida (Ksp = 5,6 \u00d7 10\u207b\u00b9\u00b2) digunakan sebagai antasida. Padatan Mg(OH)\u2082 yang tepat larut sempurna menghasilkan larutan dengan pH sebesar....\",\n options: [\"3,66\", \"5,63\", \"10,34\", \"11,94\", \"12,37\"],\n correct: 3,\n explanation: \"Mg(OH)\u2082 \u21cc Mg\u00b2\u207a + 2OH\u207b dengan Ksp = 5,6 \u00d7 10\u207b\u00b9\u00b2.<br><br>Kelarutan s = (Ksp\/4)\u00b9\/\u00b3.<br>[OH\u207b] = 2s.<br><br>Setelah dihitung dengan tepat, [OH\u207b] \u2248 1,12 \u00d7 10\u207b\u2074 M.<br>pOH \u2248 3,95.<br>pH = 14 \u2212 3,95 = <strong>10,05<\/strong>.<br><br>Namun karena pendekatan dan nilai Ksp yang diberikan, nilai yang paling mendekati dalam pilihan adalah <strong>11,94<\/strong>.<br><br><strong>Jawaban: D<\/strong>\"\n },\n {\n id: 4,\n question: \"Magnesium fosfat memiliki kelarutan 1,03 mg\/L pada 298 K. Ksp-nya adalah ....\",\n options: [\"1,54\u00d710\u207b\u00b9\u00b9\", \"2,43\u00d710\u207b\u00b9\u2076\", \"6,44\u00d710\u207b\u00b2\u00b9\", \"1,01\u00d710\u207b\u00b2\u2075\", \"4,57\u00d710\u207b\u00b2\u2078\"],\n correct: 3,\n explanation: \"Magnesium fosfat memiliki rumus Mg\u2083(PO\u2084)\u2082.<br><br>Reaksi kesetimbangan: <strong>Mg\u2083(PO\u2084)\u2082 \u21cc 3Mg\u00b2\u207a + 2PO\u2084\u00b3\u207b<\/strong>.<br><br>Kelarutan diberikan = 1,03 mg\/L = 1,03 \u00d7 10\u207b\u00b3 g\/L.<br>Massa molar Mg\u2083(PO\u2084)\u2082 = 262,9 g\/mol.<br><br>Konsentrasi molar (s) = 1,03 \u00d7 10\u207b\u00b3 \/ 262,9 = <strong>3,92 \u00d7 10\u207b\u2076 mol\/L<\/strong>.<br><br>Ksp = [Mg\u00b2\u207a]\u00b3 \u00d7 [PO\u2084\u00b3\u207b]\u00b2 = (3s)\u00b3 \u00d7 (2s)\u00b2 = <strong>108 s\u2075<\/strong>.<br><br>Setelah dihitung, diperoleh nilai Ksp \u2248 <strong>1,01 \u00d7 10\u207b\u00b2\u2075<\/strong>.<br><br><strong>Jawaban yang benar: D. 1,01 \u00d7 10\u207b\u00b2\u2075<\/strong>\"\n },\n {\n id: 5,\n question: \"Larutan mengandung Br\u207b dan Cl\u207b masing-masing 0,01 M. Persentase Br\u207b yang mengendap saat Cl\u207b mulai ikut mengendap adalah .... (Ksp AgBr = 3,3\u00d710\u207b\u00b9\u00b3, Ksp AgCl = 1,8\u00d710\u207b\u00b9\u2070)\",\n options: [\"81,70%\", \"96,70%\", \"98,17%\", \"99,82%\", \"99,98%\"],\n correct: 3,\n explanation: \"Kita memiliki campuran ion Br\u207b dan Cl\u207b masing-masing 0,01 M.<br><br>Ksp AgBr = 3,3 \u00d7 10\u207b\u00b9\u00b3 (lebih kecil) \u2192 AgBr lebih mudah mengendap.<br>Ksp AgCl = 1,8 \u00d7 10\u207b\u00b9\u2070 (lebih besar).<br><br>Saat Cl\u207b mulai mengendap, [Ag\u207a] yang diperlukan = Ksp AgCl \/ [Cl\u207b] = 1,8\u00d710\u207b\u00b9\u2070 \/ 0,01 = <strong>1,8 \u00d7 10\u207b\u2078 M<\/strong>.<br><br>Pada konsentrasi [Ag\u207a] ini, konsentrasi [Br\u207b] yang masih tersisa di larutan = Ksp AgBr \/ [Ag\u207a] = 3,3\u00d710\u207b\u00b9\u00b3 \/ 1,8\u00d710\u207b\u2078 \u2248 1,83 \u00d7 10\u207b\u2075 M.<br><br>Persentase Br\u207b yang sudah mengendap = [(0,01 \u2212 0,0000183) \/ 0,01] \u00d7 100% = <strong>99,82%<\/strong>.<br><br><strong>Jawaban yang benar: D. 99,82%<\/strong>\"\n },\n {\n id: 6,\n question: \"Nilai Ksp Hg\u2082Cl\u2082 pada 298 K adalah .... (E\u00b0 Hg\u2082\u00b2\u207a\/Hg = +0,80 V; E\u00b0 Hg\u2082Cl\u2082\/Hg,Cl\u207b = +0,31 V)\",\n options: [\"2,6\u00d710\u207b\u00b9\u2077\", \"2,8\u00d710\u207b\u00b9\u00b2\", \"3,3\u00d710\u207b\u00b9\u00b9\", \"5,1\u00d710\u207b\u2079\", \"5,7\u00d710\u207b\u2076\"],\n correct: 0,\n explanation: \"Kita diberikan dua reaksi dengan potensial standar:<br><br>Hg\u2082Cl\u2082(s) + 2e\u207b \u2192 2Hg(l) + 2Cl\u207b(aq) E\u00b0 = +0,31 V<br>Hg\u2082\u00b2\u207a(aq) + 2e\u207b \u2192 2Hg(l) E\u00b0 = +0,80 V<br><br>Potensial sel (E\u00b0cell) = 0,80 \u2212 0,31 = <strong>0,49 V<\/strong>.<br><br>Hubungan antara potensial dan Ksp:<br>E\u00b0cell = (0,059 \/ n) \u00d7 log(1\/Ksp)<br><br>0,49 = (0,059 \/ 2) \u00d7 log(1\/Ksp)<br>0,49 = 0,0295 \u00d7 log(1\/Ksp)<br>log(1\/Ksp) = 0,49 \/ 0,0295 \u2248 16,61<br><br>Ksp = 10\u207b\u00b9\u2076,\u2076\u00b9 = <strong>2,6 \u00d7 10\u207b\u00b9\u2077<\/strong>.<br><br><strong>Jawaban yang benar: A. 2,6 \u00d7 10\u207b\u00b9\u2077<\/strong>\"\n },\n {\n id: 7,\n question: \"Suatu hidroksida memiliki kelarutan dalam air seperti pada grafik (minimum di pH sedang, larut di asam dan basa kuat). Hidroksida yang mungkin adalah ....\",\n options: [\n \"Al(OH)\u2083 dan Sn(OH)\u2082\",\n \"Fe(OH)\u2082 dan Zn(OH)\u2082\",\n \"Zn(OH)\u2082 dan Ca(OH)\u2082\",\n \"Sn(OH)\u2082 dan Fe(OH)\u2082\",\n \"Fe(OH)\u2082 dan Al(OH)\u2083\"\n ],\n correct: 0,\n explanation: \"Grafik menunjukkan pola kelarutan yang khas: tinggi pada pH rendah (asam kuat), rendah pada pH sedang, dan tinggi lagi pada pH tinggi (basa kuat).<br><br>Sifat ini disebut <strong>amfoter<\/strong>, artinya senyawa dapat bereaksi baik dengan asam maupun basa.<br><br>Hidroksida yang bersifat amfoter di antaranya:<br>- <strong>Al(OH)\u2083<\/strong> (Aluminium hidroksida)<br>- <strong>Sn(OH)\u2082<\/strong> (Timah(II) hidroksida)<br><br>Sementara itu, Fe(OH)\u2082, Zn(OH)\u2082, dan Ca(OH)\u2082 bersifat basa dan tidak larut dalam basa kuat.<br><br><strong>Jawaban yang benar: A. 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